Question

A naughty boy is standing at the edge of the roof of a multistoreyed building. He throws a ball making an angle a with vertical upward direction at t = 0. But he losses his balance after throwing the ball and starts to fall att = to. The ball reaches at ground at t = 10 to. But the boy reaches at ground safety at t = 5to. The path of ball observed by the boy is

Answer 1

Answer:

Explanation: The answer is h/u= u^2÷20..

I hope it helps

Just take g=-10 because the force is acting in the opposite direction

Answer 2

Answer: parabola for 0< t < tₒ

Explanation: As a naughty boy is standing at the edge of the roof of a multi-story building. He throws a ball making an angle a with vertical upward direction at t = 0.

But he loses his balance after throwing the ball and starts to fall att = to.

The ball reaches at ground at t = 10 to.

But the boy reaches ground safety at t = 5to.

The path of the ball observed by the boy is

$S=\frac{10Vut+500}{u^{2} } \\2as=V^{2}-U^{2}\\2(-10)(s)=0-u^{2} \\-20s=-u^{2} \\s=\frac{u^{2} }{20}$

As the path of the ball observed by the boy is parabola for 0< t < tₒ.

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