Question

a nber consists of two digits whose whose sum is 9 if 27 is subtracted from the number it's digits are in the reversed find the number​

Answer 1

Assume Z is the Numer and it was a two digit number so,

Z = x+10y

x + y = 9

Z - 27 = 10x + y

Z = 10x + y + 27

10x + y + 27 = x + 10y

27 = x + 10y -10x -y

9y -9x = 27

9(y-x) = 27

y - x = (27/9) = 3

x + y = 9

Add above two

2y = 12

y = 6

x + y = 9

x + 6 = 9

x = 3

Z = 3 + (10*6)

Z = 3 + 60 = 63

Z = 63

Hope the above equation will solve many problem by just passing different values -:-)

Answer 2

Step-by-step explanation:

Answer:

36 or 63 can be the number

Step-by-step explanation:

Assuming

x as tens digit

y as ones digit

Their sum :

x + y = 9 ..... (i)

Number formed :

10x + y

Interchanging the digits :

10y + x

According to the question :

➡ (10x + y) - (10y + x) = 27

➡ 9x - 9y = 27

➡ 9(x - y) = 27

➡ x - y = 27/9

➡ x - y = 3 ..... (ii)

Subtracting both the equation :

$\bf \: x + y = 9 \\ { \underline{ \bf{x - y = 3}}} \\ \implies \bf \: 2x = 6 \\ \implies \bf \: x = 3$

Substituting the value of x in equation (i) :

➡ x + y = 9

➡ 3 + y = 9

➡ y = 6

Hence

The number can be 10x + y

or, 10(3) + 6

or, 36 either 63