A nearsighted man can clearly see objects only upto a distance of 100 cm and not beyond this. What is the number of the spectacles lens necessary for the remedy of this defect
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Answer:
To correct nearsightedness, an object placed at infinity must form an image 100 cm by the corrective lens. If ff is the focal length of the lens,
\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}
v
1
−
u
1
=
f
1
\dfrac{1}{-100}-\dfrac{1}{-\infty}=\dfrac{1}{f}
−100
1
−
−∞
1
=
f
1
Therefore focal lngth of correcetive lens is -1m.−1m.
Hence the power = -1D =−1D
Number of the spectacle=-1=−1
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