a needle of a sewing machine moves along a path of amplitude 4 cm with frequency 5 Hz. find its acceleration (1/30)s after it has crossed the mean position?
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Given:
The amplitude of machine is A=4 cm
The frequency of the machine is f=5 Hz
The time taken is 1/30 sec
To find:
The acceleration of the machine.
Solution:
The formula of acceleration is
a=(2πf)².A
Putting the above values
a=(2π5)²×4
a=200π
So the acceleration of the machine is a=200π m/sec²
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