Question

a needle of a sewing machine moves along a path of amplitude 4 cm with frequency 5 Hz. find its acceleration (1/30)s after it has crossed the mean position?​

Answer 1

Given:

The amplitude of machine is A=4 cm

The frequency of the machine is f=5 Hz

The time taken is 1/30 sec

To find:

The acceleration of the machine.

Solution:

The formula of acceleration is

a=(2πf)².A

Putting the above values

a=(2π5)²×4

a=200π

So the acceleration of the machine is a=200π m/sec²

Answer 2

Answer:

this is the answer

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