a needle of length 2cm is placed perpendicular to the principle axis of a concave mirror of focal length 20cm at 40cm from the mirror.The magnification of image formed is
a. -1/3
b. -1
c. -2
d. -1/2
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Answer:
-1 is the answer
Explanation:
according to the question concave mirror focal length is 20cm and the images formed at 40 cm so the image is formed at the centre of curvature it means that image distance and the height distance is same therefore the image distance is -40 cm so,
m = -v/u
m = -(-40)/-40
m= -1
hope it helps...
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