A needle of sewing machine moves along path of amplitude 2cm with frequency 10Hz find acceleration (1/40) second after it has crossed mean position
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Answer:
Given:
The amplitude of machine is A=4 cm
The frequency of the machine is f=5 Hz
The time taken is 1/30 sec
To find:
The acceleration of the machine.
Solution:
The formula of acceleration is
a=(2πf)².A
Putting the above values
a=(2π5)²×4
a=200π
So the acceleration of the machine is a=200π m/sec²
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