A negligibly small current is passed through a wire of length 15 m and of uniform cross-section 6.0*10-7 m
2
and its resistance
is measured to be 5.0 Ώ.What is the resistivity of the material at the temperature of the experiment?
Answers
Answered by
67
Hey.
Here is the answer.
As, R = p L/A
and , R = 5 ohm ; L= 15m ; A = 6×10^-7m^2
So, resistivity, p = RA/L = 5×6×10^-7/15
or, resistivity , p = 2×10^-7 Ώm
Thanks.
Here is the answer.
As, R = p L/A
and , R = 5 ohm ; L= 15m ; A = 6×10^-7m^2
So, resistivity, p = RA/L = 5×6×10^-7/15
or, resistivity , p = 2×10^-7 Ώm
Thanks.
Answered by
26
..... hope it helps ......
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