A neon discharge tube 2.9 ions move to the right each second while 1.2 electorns left current in discharge tube
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In a neon discharge tube, 2.9 x 1018 Ne+ ions move to the right per second, while 1.2 x 1018 electrons move to the left per second. The current in the discharge tube is?
answer. Net current i = (2.9 * 10^18 + 1.2 * 10^18)* e = 4.1 * 10^18 * 1.6 * 10^-19
= 0.656 amp towards right
I hope this will help you
if not then comment me
In a neon discharge tube, 2.9 x 1018 Ne+ ions move to the right per second, while 1.2 x 1018 electrons move to the left per second. The current in the discharge tube is?
answer. Net current i = (2.9 * 10^18 + 1.2 * 10^18)* e = 4.1 * 10^18 * 1.6 * 10^-19
= 0.656 amp towards right
I hope this will help you
if not then comment me
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Answer:
= 0.656 amp towards right
Hope you understand
Explanation:
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