a net force of 15 Newtons applied to a cart with a mass of 2.1 kg
a. what is the acceleration of the cart
b. how long will it take the cart to travel 2.8 M starting from rest
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Heya, Here is your Answer :-
a) Force,F = 15 N
Mass,M = 2.1 kg
Acceleration,a = ?
♠
So,
♠
a = 15/2.1
a = 7.142857 m/s^2
So,
The Acceleration , a is 7.142857 m/s^2
b) Distance,S = 2.8 m
Acceleration,a = 7.14 m/s^2
Initial Velocity,u = 0
Time,t = ?
♠
So,
2.8 = 0 + 7.14*t^2/2
t = 0.885615 s
So,
The Cart took 0.885615 seconds to cover a Distance of 2.8 metres.
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a) Force,F = 15 N
Mass,M = 2.1 kg
Acceleration,a = ?
♠
So,
♠
a = 15/2.1
a = 7.142857 m/s^2
So,
The Acceleration , a is 7.142857 m/s^2
b) Distance,S = 2.8 m
Acceleration,a = 7.14 m/s^2
Initial Velocity,u = 0
Time,t = ?
♠
So,
2.8 = 0 + 7.14*t^2/2
t = 0.885615 s
So,
The Cart took 0.885615 seconds to cover a Distance of 2.8 metres.
If you got some help from this Solution then pls. mark it the Brainliest..✌✌
Please Please Please Mark me the Brainliest..
I need it ....✌✌
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