Question

A net force of 20 N acts on a 5kg mass kept at rest. Distance travelled by the mass in 6 s is

Answer 1

hi there!!

hope the answer is useful

Answer 2

Given :
Force=F=20N
mass=5kg
initial velocity= u=0 m/s
t=6s
S=distance=?
We know that, F= ma
a=F/m
=20/5
=4m/s²
Distance travelled = S= ut+1/2at²
=0xt+1/2x4x(6)²
=1/2 (4x36)
=144/2
=72 m
Distance travelled = 72m.