Question

a net force of 20 n acts on an object of mass of 5 kg. distance travelled by the mass in 6 s

Answer 1

F = m × a
a = 20/5
a = 4m/s^2
s= ut + 1\2at^2
s = 0×t + 1/2×4×(6)^2
s = 2×36
s = 72m
so the distance is 72m
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Answer 2

force = mass x acceleration
acceleration = force / mass
= 20/5
= 4 m/s^2

we know
S = ut + 1/2 at^2
S= 0(6) + 1/2 (4)(6)(6)
S= 0+ 72
S=72 m

distance = 72 m