A net force of 50N acts on a 5kg mass kept at rest. Distance travelled by the mass in 6s is
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Answered by
1
now given us that F=50N
M=5Kg, t=6sec
now
F=Ma
50=5×a
a=10m\s^2
Now
here in question u = 0 is missing
by kinematical equation
s =ut×1\2at^2
=0*t*1\2*10*6*6.
=180m
M=5Kg, t=6sec
now
F=Ma
50=5×a
a=10m\s^2
Now
here in question u = 0 is missing
by kinematical equation
s =ut×1\2at^2
=0*t*1\2*10*6*6.
=180m
Answered by
0
Speed=distance/) time. 23/6=38.33answer
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