Question

A net force of 9.0 n acts through a distance of 3.0 m in a time of 3.0 s. the work done is

Answer 1

Force = 9 N
Displacement = 3m
work=F ˣ S
       = 9 ˣ 3
        =27 J

Answer 2

The work done in 3 sec on the body is 27 J.

Solution:

The total force acting on the body through a distance is given in a particular amount of time, its work done be calculated as following,

The work done is obtained by multiplying the force with the amount of displacement in the object.

Work done = Force x Displacement  

$\begin{array}{l}{W=F \times s} \\ {W=9 \times 3} \\ {W=27 J}\end{array}$