Question

A netball team played 77 games. Each game was won, drawn or lost. number of games won : number of games drawn : number of games lost = 5:4:2. Work out how many more games the team won than the team lost

Answer 1

✨Answer✨:

The team won 21 matches more than the matches they lost.

✨Step-by-step explanation✨:

✨Given✨:

Number if matches played = 77

The ratio of number of games won to number of games drawn to number of games lost = 5:4:2

✨To Find✨:

The number of more games the team won than the team lost.

✨Solution✨:

Let the common multiple be 'x',

Then the numbers become 5x, 4x and 2x.

Equation Formed:

5x + 4x + 2x = 77

11x = 77

x = $\frac{77}{11}$

x = 7

So, now the numbers are:

5x = 5 × 7 = 35

4x = 4 × 7 = 28

2x = 2 × 7 = 14

Overall:-

Number of games won = 35

Number of games drawn = 28

Number of games lost = 14

Now we will find the number of games won more than number of games lost,

For that we need we need to subtract he number of games won from number of games lost

⇒ 35 - 14

⇒ 21

Number of Games Won more than Number of Games Lost = 21

Hence, the netball team won 21 games more than the games they lost.