Math, asked by aniketprakash1968, 4 months ago

A Netherlands based gangster Rajan Madan is in India these days. He wants to rob a big bank in India, whose locker
code according to his insider info is an odd number between 50 and 450. He also knows that the numbers are from the set:{0, 1, 2, 3, 4,5). How many maximum trials he has to take to unlock the locker?
a. 110
b. 72
c. 78
d. 60​

Answers

Answered by TheSarcasticSmile
3

Answer:

c. 78

Step-by-step explanation:

hope it helps yOu.....

Answered by smithasijotsl
0

Answer:

The correct answer is option (b) 72

Step-by-step explanation:

To find,

The number of possible  odd numbers between 50 and 450 using the numbers from the set {0,1,2,3,4,5}

Total number of odd numbers between 50 and 450 = Number of odd numbers between 50 and 100 + The number of odd numbers between 100 and 400 +The number of odd numbers between 400 and  450

Number of odd numbers between 50 and 100 using digits  {0,1,2,3,4,5}

All the numbers between 50 and 100 are two-digit numbers

The possible digits in tens place = 5

The number of possible digits in the tens place = 1

The possible digits in the ones place = 1,3,5

The number of possible digits in the ones place = 3

Total number of possible numbers between 50 and 100 = 1×3 = 3

The number of odd numbers between 100 and 400 using digits  {0,1,2,3,4,5}

The possible digits in the hundreds place = 1,2,3

The number of possible digits in the hundred's place = 3

The possible digits in the tens place = 0,1,2,3,4,5

The number of possible digits in the tens place = 6

The possible digits in the ones place = 1,3,5

The number of possible digits in the ones place = 3

Total number of possible numbers between 100 and 400  = 3×6×3 = 54

Also, 100 and 400 are not odd numbers

The number of odd numbers between 400 and 450 using digits  {0,1,2,3,4,5}

The possible digits in the hundreds place = 4

The number of possible digits in the hundred's place = 1

The possible digits in the tens place = 0,1,2,3,4

The number of possible digits in the tens place = 5

The possible digits in the ones place = 1,3,5

The number of possible digits in the ones place = 3

Total number of possible numbers between 100 and 400  = 1×5×3 = 15

Hence the total possible numbers are 3+54+15 = 72

∴ The number of possible odd numbers between 50 and 450 using the numbers from the set {0,1,2,3,4,5} = 72

Hence the correct answer is option (b) 72

#SPJ3

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