Question

a network of 4 ohm 4 ohm and 3 ohm resistance are connected to 10 volt battery.compute the equivalent resistance and current obtained from battery

Answer 1

$\huge\sf\pink{Answer}$

☞ Resistance = 10/11 Ω

☞ Current = 0.90 A

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$\huge\sf\blue{Given}$

✭ Three Resistors of 4 Ω, 4 Ω and 3 Ω connected in series

✭ Voltage (v) = 10 V

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$\huge\sf\gray{To \:Find}$

◈ Equivalent Resistance?

◈ Current in the circuit?

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$\huge\sf\purple{Steps}$

So here as the Resistors are connected in series (network) then the net resistance will be given by,

$\underline{\boxed{\red{\sf R_{net} = R_1+R_2+R_3...+R_n}}}$

Substituting the given values,

➳ $\sf R_{net} = 4\Omega + 4\Omega + 3 \Omega$

➳ $\sf\green{ R_{net} = 11 \Omega}$

So now that we know the value of resistance to find the current in the circuit we can use the Ohm's law,that is,

$\underline{\boxed{\red{\sf V = IR}}}$

Substituting the values,

➝ $\sf 10 = I \times 11$

➝ $\sf \dfrac{10}{11} = I$

➝ $\sf\orange{ I = 0.90 A}$

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