Science, asked by harshkajal1212, 8 months ago

A network of four capacitors,each capacitance 30PF is connected across a baterry of 60V shown in figure. find the net capacitance and energy stored capictor​

Answers

Answered by Anonymous
0

Answer:

Here C  

1

​  

,C  

2

​  

,C  

3

​  

 are in series and the equivalent resistance for these is C  

123

​  

=30/3=10μF

Now C  

123

​  

,C  

4

​  

 are in parallel. So the net capacitance C  

net

​  

=C  

123

​  

+C  

4

​  

=10+30=40μF

Now potential across C  

123

​  

 and C  

4

​  

 is same i.e, 60V

So energy stored in C  

4

​  

 is U  

4

​  

=  

2

1

​  

C  

4

​  

V  

2

=0.5×30×10  

−6

×60  

2

=0.054J=54mJ

As C  

1

​  

,C  

2

​  

,C  

3

​  

 are in series so they have same charge is equal to Q  

123

​  

=C  

123

​  

V=10×60=600μC

Stored energy, U  

1

​  

=  

2C  

1

​  

 

Q  

123

2

​  

 

​  

=  

2×30×10  

−6

 

(600×10  

−6

)  

2

 

​  

=6mJ

As C  

1

​  

,C  

2

​  

,C  

3

​  

 have same charge and same capacitance so they store same energy.

Thus, U  

1

​  

=U  

2

​  

=U  

3

​  

=6mJ

Explanation:

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