A network of four capacitors of capacity equal to C₁ = C, C₂ = 2C, C₃ = 3C and C₄ = 4C are conducted to a battery as shown in the figure. The ratio of the charges on C₂ and C₄ is(a) 4/7(b) 3/22(c) 7/4(d) 22/3
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I hope this is correct
answer is 3/22
answer is 3/22
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Answer:
B) 3/22
Explanation:
Capacitors C₁ = C, C₂ = 2C, C₃ = 3C and C₄ = 4C ( Given)
Since C1 C2 and C3 are in series -
1/C' = 1/C+1/2C+1/3C
1/C' = 6+3+2/6
1/C'= 6C/11
All the capacitors in branch 1 is in series therefore,
charge on each capacitor Q = 6/11CV
Also charge on capacitor C4 is Q = 4CV
Therefore the ratio = Q'/Q
= 6CV/11×4CV = 3/22
Thus, the ratio of the charges on C₂ and C₄ is 3/22
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