Question

A network of resistors is connected to a 16V battery with internal resistance of 1 ohm, as shown in the following figure. Compute the equivalent resistance of the network. Pls refer to the pic below.

Answer 1

Given: A network of resistors is connected to a 16V battery with internal resistance of 1 ohm.

To find: The equivalent resistance of the network.

Solution:

• So there are some resistance in series and some in parallel. So first lets calculate the resistance in parallel.

• The first combination is of 4 and 4 ohm

         R(parallel) = 1/ R1 + 1 / R2

                           = 1 / 4 + 1 / 4

                           = 2 / 4

                          = 1 / 4         ...............(i)

         R(parallel) = 1/ R1 + 1 / R2

                           = 1 / 12 + 1 / 6

                           = 1 / 12 + 2 / 12

                           = 3 / 12

                          = 1 / 4       ..............(ii)

• Now adding these two with series resistors, we get:

          = 1/4 + 1/4 + 1 + 1  

          = 2/4 + 2

          = 1/2 + 2

          = 5/2

Answer:

         So the equivalent resistance of the network is 5/2.