Question

A network of resistors is connected to a 16v battery with internal resistance 1ohm find equivalent resistance of the network total currene of circuit

Answer 1

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Problem:- A network of resistors is connected to a 16 V batterywith internal resistance of 1Ω, as shown in Fig. (a) Computethe equivalent

Answer 2

Answer:

So the equivalent resistance of the network is 5/2.

Explanation:

Given: A network of resistors is connected to a 16V battery with internal    resistance of 1 ohm.

To find: The equivalent resistance of the network.

Solution:

So there are some resistance in series and some in parallel. So first lets calculate the resistance in parallel.

The first combination is of 4 and 4 ohm

        R(parallel) = 1/ R1 + 1 / R2

                          = 1 / 4 + 1 / 4

                          = 2 / 4

                         = 1 / 4                            (i)

        R(parallel) = 1/ R1 + 1 / R2

                          = 1 / 12 + 1 / 6

                          = 1 / 12 + 2 / 12

                          = 3 / 12

                         = 1 / 4                          ..(ii)

Now adding these two with series resistors, we get:

         = 1/4 + 1/4 + 1 + 1  

         = 2/4 + 2

         = 1/2 + 2

         = 5/2