Question

A network using csma/cd has a bandwidth of 10 mbps. If the maximum propagation time including the device delays is 25.6 s, what is the minimum size of the frame?

Answer 1

Explanation:

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Answer 2

Concept Introduction:-

Computer networking is the term for interconnected computing equipment that may share resources and exchange data.

Given Information:-

We have been given that a network using csma/cd has a band width of $10$ mbps. If the maximum propagation time including the device delays is $25.6$ s.

To Find:-

We have to find that the minimum size of the frame.

Solution:-

According to the problem

The minimum frame transmission time is $Tfr = 2 \times Tp = 51.2$ μs. This means, in the worst case, a station needs to transmit for a period of $51.2$μs to detect the collision.

The minimum size of the frame is $10$ Mbps$\times 51.2$ μs $= 512$ bits or $64$ bytes. This is actually the minimum size of the frame for Standard Ethernet.

Final Answer:-

The minimum size of the frame is $64$ bytes.

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