Question

A network using csma/cd has a bandwidth of 10 mbps. If the maximum propagation time including the device delays is 25.6 s, what is the maximum size of the frame?a

Answer 1

Explanation:

The minimum frame transmission time is Tfr = 2 × Tp = 51.2 μs. This means, in the worst case, a station needs to transmit for a period of 51.2 μs to detect the collision.

The minimum size of the frame is 10 Mbps × 51.2 μs = 512 bits or 64 bytes. This is actually the minimum size of the frame for Standard Ethernet.