Question

A neutral atom of an element has 2K,8L,11M and 2N electrons. The number of p-electrons in the atom are. Answe is 10 electrons

Answer 1

2*1=2
8*2=14
11*3=33
2*4= 8 Electrons.

Answer 2

Answer: There are total 12 electrons present in p orbitals that is 6 in 2-p orbital and 6 in 3-p orbital.

Explanation:

Given :

K,L, M and N are the name of the energy levels or shells and there numeric  designation are:1 = K , 2 = L , 3 = M , 4 = N .

A neutral atom of an element has 2K , 8L , 11M and 2N electrons .

There are total 23 electrons in a neutral atom  .The atomic number of the neutral atom is 23 and its name is vanadium (V)

The electronic configuration of the will be:  

$[V]=1s^22s^22p^63s^23p^64s^23d^{3}$

There are total 12 electrons present in p orbitals that is 6 in 2-p orbital and 6 in 3-p orbital.