a neutral atom of an element has two 'K' ,eight 'L' ,nine 'M' and two 'N' electrons. the total number of electrons present in the subshell having L value 0 is.optionalso there that you can see from that picture.
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Answers
The Given Neutral atom Contains a total of : (2 + 8 + 9 + 2) = 21 Electrons
As it is a Neutral atom : Number of Electrons = Number of Protons
⇒ The Atomic Number of Given Neutral Atom is 21
⇒ The Electronic Configuration of the Given Neutral atom is :
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹
We know that For 's' sub-shell, Azimuthal Quantum number (l) = 0
⇒ From the Electronic Configuration :
We can Notice that there are total of (2 + 2 + 2 + 2) = 8 's' sub-shell electrons.
⇒ The Total Number of Electrons Present in the sub-shell having l value zero is 8
Option (2) is the Answer.
Answer:
option 2: 8
A neutral atom of an element has 2K, 8L, 9M and 2N electrons so it has total electrons of 21.
So it has 21 protons and its atomic no is 21
And electronic configuration of element is:
1s2 2s2 2p6 3s2 3p6 3d1 4s2
So, the number of s electrons are 8.