A neutral block of density 9000 kg/m3 weighs 6oN in all find its height when it is immerse in parafin wax of density 800kg/m3 (take g =10m/s2
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Explanation:
The mass of the metal block is found by using the equation
W=mg
solving the equation for m gives
m=W/g
Where
W= weight= 60N
m=mass= unknown
g= acceleration due to gravity= 9.80m/s^2
m=60/9.80=6.122kg
the volume of the metal box is found by using the equation
d= m/v
solving for v gives
v=m/d
where d= density= 9000kg/m^3
m= mass= 6.122kg
v=volume= unknown
v= 6.122/9000=0.00068m^3
the buoyant force when immersed in paraffin wax of density 800kg/m^3 is found by using the equation
F_b= pVg
Where
p= density of the paraffin wax= 800kg/m^3
V=volume of the metal box=0.00068m^3
g= acceleration due to gravity= 9.80m/s^2
F_b= 800*0.00068*9.80=5.33N
New weight of the metal object = 60N-5.33=54.67N
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