Physics, asked by aaditya2596, 19 days ago

A neutral block of density 9000 kg/m3 weighs 6oN in all find its height when it is immerse in parafin wax of density 800kg/m3 (take g =10m/s2

Answers

Answered by Devesh45222
1

Explanation:

The mass of the metal block is found by using the equation

W=mg

solving the equation for m gives

m=W/g

Where

W= weight= 60N

m=mass= unknown

g= acceleration due to gravity= 9.80m/s^2

m=60/9.80=6.122kg

the volume of the metal box is found by using the equation

d= m/v

solving for v gives

v=m/d

where d= density= 9000kg/m^3

m= mass= 6.122kg

v=volume= unknown

v= 6.122/9000=0.00068m^3

the buoyant force when immersed in paraffin wax of density 800kg/m^3 is found by using the equation

F_b= pVg

Where

p= density of the paraffin wax= 800kg/m^3

V=volume of the metal box=0.00068m^3

g= acceleration due to gravity= 9.80m/s^2

F_b= 800*0.00068*9.80=5.33N

New weight of the metal object = 60N-5.33=54.67N

Similar questions