Question

A neutral water molecule in its vapour state has an electric
dipole moment of 6•2x10^-30Cm. If is placed in an
electric feild of 1.5 x 10^4 N/c. How much work must an
external agent do to turn this molecule end
for end in this fild, starting from its fully aligned
position (theta = 90°)? [Hint: W = Uf - Ui)​

Answer 1

Answer:

P=2×10

−24

Cm

E=2×10

4

NC

τ=EP=2×10

−24

×2×10

4

=4×10

−20

Nm