Question

A neutron is moving with energy 10 keV. If the mass of the neutron is 1.675×10-27 kg, what is the de Broglie wavelength associated with it

Answer 1

Hey Dear,

◆ Answer -

λ = 2.864×10^-13 m

● Explaination -

# Given -

E = 10 KeV = 10×10^3×1.6×10^-19 = 1.6×10^-15 V

# Solution -

de Broglie's wavelength of neutron is calculated by -

λ = h / √(2mE)

λ = 6.63×10^-34 / √(2 × 1.675×10^-27 × 1.6×10^-15)

λ = 6.63×10^-34 / 2.315×10^-21

λ = 2.864×10^-13 m

Therefore, de Broglie wavelength would be 2.864×10^-13 m.

Hope this helps you...