Question

a new car cost rupees 480000 if its price depreciates at the rate of 8% during first two year and at the rate of 20% a year there after what will be the price of three years​

Answer 1

Answer:

price after 2 years =480000(1-8/100)^2

=480000(0.92)^2

price after 3 year =480000(0.92)^2(1-20/100)^1

=480000×0.92^2×0.8

=3250.18