a new car is purchased for Rs 250000 its value depreciates at the rate of 10% in the first year 8% in second year and 6th % every year find its value after 4 years
Answers
Thus the value of car after 4 years will be 183,000 Rs.
Step-by-step explanation:
Initial value of the car, P= Rs 250000
Rate of depreciation for the first year, p= 10%
Rate of depreciation for the second year, q= 8%
Rate of depreciation after 3rd year r = 6 %
Rate of depreciation after 4th year s = 6 %
Time, n = 4 years
The value of the car after 4 years is = {P × (1 − p / 100) × (1 − q / 100)} x 9 1 - r / 100 ) x ( 1 - s / 100 )
= Rs { 250000 x ( 1 - 10 / 100 ) x ( 1 - 8 / 100 ) x ( 1 - 6 / 100 ) x ( 1 - 6 / 100)
= Rs { 250000 x (1 - 0.1) x ( 1 - 0.08) x ( 1 - 0.06) x ( 1- 0.06)}
= Rs { 250000 x 0.9 x 0.92 x 0.94 x 0.94}
= Rs 250000 x 0.732
= Rs 183,000
Thus the value of car after 4 years will be 183,000 Rs.
Answer :-
Thus the value of car after 4 years will be 183,000 Rs.
Step-by-step explanation:
Initial value of the car, P= Rs 250000
Rate of depreciation for the first year, p= 10%
Rate of depreciation for the second year, q= 8%
Rate of depreciation after 3rd year r = 6 %
Rate of depreciation after 4th year s = 6 %
Time, n = 4 years
The value of the car after 4 years is = {P × (1 − p / 100) × (1 − q / 100)} x 9 1 - r / 100 ) x ( 1 - s / 100 )
= Rs { 250000 x ( 1 - 10 / 100 ) x ( 1 - 8 / 100 ) x ( 1 - 6 / 100 ) x ( 1 - 6 / 100)
= Rs { 250000 x (1 - 0.1) x ( 1 - 0.08) x ( 1 - 0.06) x ( 1- 0.06)}
= Rs { 250000 x 0.9 x 0.92 x 0.94 x 0.94}
= Rs 250000 x 0.732
= Rs 183,000
Thus the value of car after 4 years will be 183,000 Rs.