Question

A new deadly virus has been accidentally injected into a patient at 8:30 AM. The species mutates in such a way
that every individual produces exactly 2 offspring exactly after 1 hr. All individuals die exactly when offspring of
their 3rd generation produces their offspring. When the active population of the vi,rus reaches 3500 the patient
will die. There is an antidote whijch will kill all virus if injected into the patient the very second it is
administered.
Find what is the max time before which the patiient needs to be iinjected to be alive?
Note: Enter t he time in 24 hour format. Eg. 1:45 PM should be entered as 13:45

Answer 1

Answer:

Answer is 0

Step-by-step explanation:

plz make me brainliest please

Answer 2

Answer:

The patient need antidote before 20.30 PM

Step-by-step explanation:

Given data

⇒ A deadly virus has been accidentally injected  into a patient at 8.30 AM

⇒ the virus species mutates in such a way that every individual produces exactly 2 offspring after 1 hour  

⇒ all individual species will die exactly when offspring of their 3rd generation produces their offspring

⇒ when the active population of the virus reaches 3500 the patient will die

⇒ there is antidote which will kill all virus if injected into the patient the very second it is administered

Here we need to find the max time before which the patient needs to be alive

Explanation

from data every virus will produce exactly 2 offspring exactly after 1 hour    

⇒ if it is started with one virus  

 one virus will became 2 viruses ⇒ after 1 hr ⇒ 2¹

 2 virus will become 4 viruses  ⇒ after 2 hrs ⇒ 2²

like exactly after 13 hrs the virus population will be 2¹² = 4096  

⇒ and mean while all individual virus will die after their 3rd generation produces their offspring which means

after 3 hrs the first most virus's 3rd generation will produce their offspring then the first virus will die observe the whole thing in flowing table

    time        count of production      count of destruction  

    0 hrs           1  =  1 virus                             -

after 1 hr          2¹ = 2                                     -  

after 2 hrs       2² = 4                                     -

after 3 hrs       2³ = 8                                    1

after 4 hrs       2⁴ = 16                                   2 = (2¹)

after 5 hrs      2⁵ = 32                                  4 = (2²)    

⇒ like this after 12 hrs

  virus population = 2¹² - 2⁹ = 4096 -512 = 3584

⇒ the patient will die after 12 hrs so he need antidote within 12 hrs to be alive    

⇒ he injected at 8.30 PM, so add 12 hrs (8.30 +12 hrs)

⇒ the patient need antidote before 20.30 PM