Math, asked by axelseve142005, 6 months ago

A new enviromentally friendly garden fertilizer mixtures contains 2 parts of special organic X, 2 parts of the special organic Y and 3 parts of the special organic Z.

How many kilograms of the special organic Z is there ina a bag of fertilizer which weighs 56 kilograms?

Answers

Answered by sateesh141996
1

Answer:

Special organic Z = 24 kg

Step-by-step explanation:

Using ratio proportion

Ratio of organic fertilizer

= X: Y : Z = 2: 2: 3

Given that total bag weighs 56 kg

Now

2x + 2x + 3x = 56

7x = 56

x = 8

organic X = 2x = 2(8)

= 16 kg

organic Y = 2x

= 16 kg

organic Z = 3x = 3(8)

= 24 kg

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