Question

A new galvanic cell of E^u more than E°dl of Daniel cell is connected to Daniel cell in a manner that new cell gives electrons to cathode, what will happen
(a) Ecell will increase
(b) Ecell will decrease
(c) No change will take place
(d) Daniel cell will work as electrolytic cell where Zn will be deposite on zinc rod and copper will dissolve from copper rod.

Answer 1

Answer:

The Nernst Equation enables the determination of cell potential under non-standard conditions. It relates the measured cell potential to the reaction quotient and allows the accurate determination of equilibrium constants (including solubility constants).

Answer 2

d) The Daniel cell will work as an electrolytic cell where Zn will be deposited on the zinc rod and copper will dissolve from the copper rod.

• When a galvanic cell of E^u more than E^dl of Daniel cell is connected in a manner that the new cell gives electrons to the cathode, then the Daniel cell will work as an electrolytic cell where Zn will be deposit on zinc rod and copper will dissolve from the copper rod.

• This is because the external emf will be greater than the emf of Daniel's cell. This will make the cell act as electrodes leading to the transfer of zinc on the rod and copper will get dissolved from the copper rod.

• The flow of current is reversed. That is, the Anode behaves as Cathode and the vice versa.

Hence, the correct option is d) Daniel's cell will work as an electrolytic cell where Zn will be deposited on the zinc rod and copper will dissolve from the copper rod.

#SPJ2