Question

A new road that connects Uniontown to Springville is 4 1/3 miles long. What is the change in distance when using the new road instead of the dirt roads? Write your answer as a mixed number.

Answer 1

Step-by-step explanation:

So it is stated that there are 2 dirt roads with the

given measurements. let us add the two first

Dirt road=23/8miles+35/6miles

Dirt road=19/8miles+23/6miles

Dirt road=(114/48+184/48)=298/48miles

The difference is

Difference=298/48-41/3

Difference=298/48-13/3

Difference=298/48-208/48=90/40

42/48=17/8

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Answer 2

Note: The given question is incomplete as it should be as follows:

A new road that connects Uniontown to Springville is $4\frac{1}{3}$ miles long. What is the change in distance when using the new road instead of the dirt roads? Write your answer as a mixed number. (Measurements of the dirt roads: $2\frac{3}{8}$ miles and $3\frac{5}{6}$ miles).

Given: distance between the new road and Springville is $4\frac{1}{3}$ miles.

Measurements of the dirt roads: $2\frac{3}{8}$ miles and $3\frac{5}{6}$ miles.

To find: change in the distance when using the new road.

Solution:

Know that from the question, there are 2 dirt roads with the given measurements.

Add the distance of the two dirt roads.

dirt road$= 2\frac{3}{8} miles + 3\frac{5}{6} miles$

dirt road$= \frac{19}{8} miles + \frac{23}{6} miles$

dirt road $= \frac{114}{48} + \frac{184}{48}$

               $= \frac{298}{48} miles$

Find the difference between the dirt roads and new road.

difference $=\frac{298}{48} - 4\frac{1}{3}$

                   $=\frac{298}{48}-\frac{13}{3}$

                  $=\frac{298}{48} - \frac{208}{48}$

                  $= \frac{90}{48}$

                  $= 1\frac{42}{48}$

                   $= 1\frac{7}{8}$ miles.

Hence, the change in distance when using the new road instead of the dirt roads is $1\frac{7}{8}$ miles.