Question

A new scale N of temperature is divided in such a way that the freezing point of water is 100°N and
the boiling point is 400° N. The Celsius and the new temperature scale readings will be same at



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Answer 1

Answer:

Explanation:

Refer to following explanation attached image file.

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Answer 2

Answer:

The Celsius and new temperature will be the same at -50*C or -50*N.

Explanation:

Given that,

A new scale N of temperature is divided in such a way that the freezing point of water is 100°N and the boiling point is 400°N.

We are required to find the temperature where Celsius and new temperature readings will be the same.

For temperature scales, we have a relation as follows

$\frac{x-L}{U-L}=Constant$

x=Temperature scale

U=Upper temperature/Boiling point.

L=Lower temperature/Freezing point.

Therefore, For the new scale, we write

$\frac{^{0}N-100}{400-100} =k= > \frac{^{0}N-100}{300}=k--- > (1)$

For the Celsius scale, we write

$\frac{^{0}C-0}{100-0} =k= > \frac{^{0}C}{100}=k--- > (2)$

Equating both the equations we get

$\frac{^{0}N-100}{300} =\frac{^{0}C}{100}\\= > ^{0}N=3^{0}C+100$

Now we are required to find the temperature at which both scales give the same reading

$= > ^{0}N=^{0}C\\= > ^{0}C=3^{0}C+100\\= > ^{0}C=-50$

Therefore,

The Celsius and new temperature will be the same at -50*C or -50*N.

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