Question

A new scale N of temperature is divided in such a way that the freezing point of ice is 50°N
and the boiling point is 300°N. What is the temperature reading on this new scale when the
temperature is 150°C? At what temperature both the Celsius and the new temperature scale
reading would be the same?

Answer 1

Answer:

7 A new scale N of temperature is divided in such a way that the ed in such a way that the freezing point of water is 100° N and boiling point is 400°N. The Celsius and new temperature scale reading is and new temperature scale readings will be same at 1-40°C 2) 40°C (3) -50°C 4) 50°C - 11 f the come.

Explanation:

7 A new scale N of temperature is divided in such a way that the ed in such a way that the freezing point of water is 100° N and boiling point is 400°N. The Celsius and new temperature scale reading is and new temperature scale readings will be same at 1-40°C 2) 40°C (3) -50°C 4) 50°C - 11 f the come.

Answer 2

Answer:

The Celsius and new temperature will be the same at -12.5°C. or -12.5N.

Concept:

Temperature conversion:

It relate to the conversion of temperature values across units. There are numerous ways to convert temperatures. The most popular units of measurement among these are Kelvin, Celsius, and Fahrenheit. The Kelvin scale states that water has a freezing point of 273.15K and a boiling point of 373.15K. Water has a freezing point of 32°F and a boiling point of 212°F on the Fahrenheit scale. The freezing point of water is 0°C, and the boiling point is 100°C, according to the Celsius system.

Given:

Freezing point of ice = 50°N

Boiling point = 300°N

Find:

We have to find the temperature reading at 150°C.

Solution:

As we know from temperature conversion formula:

$(\frac{T_{N}-FP }{BP - FP} )_{N} = {(\frac{T_{C}-FP }{BP - FP})_{^{\circ} C}$

where, FP = Freezing point and BP = Boiling point.

$\frac{T_{N}- 50 }{300-50} = \frac{T_{C} - 0}{50 - 0}$

Now, by solving we get:

$T_{N} - 50 = 5T_{C}$

$T_{N} = T_{C}$

$T_{C} - 50 = 5 T_{C}$

$-50 =$ $4T_{C}$

$T_{C} = -12.5 ^{\circ} C$

Therefore, the Celsius and new temperature will be the same at -12.5°C. or -12.5N.

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