Question

A new test vehicle will accelerate at a steady 4 m/s2 over a 500-m track. How long will the vehicle take to travel the track?​

Answer 1

Explanation:

u=0

a=4m/s2

s=500m

t=?

finding v

2as=v^2-u^2

2(4)(500)=v^2-(0)^2

4000=v2-0

√4000=v

v=63.24

finding t

s=ut+1/2at^2

500=0+2t^2

500/2=t2

√250=t

t=15.81s

Answer 2

The time taken by the vehicle is 15.81 meters.

Explanation:

Given that,

Acceleration of the vehicle, $a=4\ m/s^2$

Distance covered by the vehicle, d = 500 m

Initial speed of the vehicle, u = 0

To find,

Time taken by the vehicle to travel the track.

Solution,

Let t is the time taken by the vehicle. It can be calculated using equation of motion as :

$d=ut+\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}at^2$

$t=\sqrt{\dfrac{2d}{a}}$

$t=\sqrt{\dfrac{2\times 500}{4}}$

t = 15.81 seconds

So, the time taken by the vehicle is 15.81 meters. Hence, this is the required solution.

Learn more,

Kinematics

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