A nichrome wire has a resistance of 5 ohm. Find the resistance of another nichrome wire whose length is 4 times and the area wa cross section 3 times of the first wire... please ans.................
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Answer:
et the length of the first nichrome wire=l then the length of the second nichrome wire =4l,...................................let the cross section area of the first wire =A then,the cross section area of the second wire =3A.....................let resistance of the first wire =R1 and resistance of second wire =R2....then,R1/R2=(p×l/A)/(p×4l/3A)=3/4............now,it is given that resistance of first wire is 5 ohm so,R1/R2=3/4=>5/R2=3/4...=>R2=20/3=6.67 ohm(ans
Explanation:
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10
Answer:
ANSWER = 6.67 (OHM)
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