a nichrome wire has a resistance of 6 ohm. what will be the resistence of another made of the same material having length 3 times and area 2 times that of the first wire
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for nichrome wire :
R₁ = resistance = 6 ohm
ρ = resistivity
L₁ = length
A₁ = area
resistance is given as
R₁ = ρL₁/A₁ eq-1
for other wire :
R₂ = resistance = 6 ohm
ρ = resistivity
L₂ = length = 3L₁
A₂ = area = 2A₁
resistance is given as
R₂ = ρL₂/A₂
R₂ = ρ (3L₁)/(2A₁)
R₂ = (1.5) (ρL₁/A₁ )
using eq-1
R₂ = (1.5) R₁
R₂ = (1.5) (6)
R₂ = 9 ohm
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