A nichrome wire of 4 ohm resistance is doubled on it. calculate the new resistance of the wire.
Answers
Answered by
16
We consider wire is doubled on it means to fold the length of wire. It means its length will get half and area of cross section will get doubled.
∴ Let the resistance of the wire originally 'R' of length 'L' and area of cross-section 'A' with resistivity of material is 'p',
Then
R = p l/A = 4Ω
Now, for new arrangement,
p' = p
l' = l / 2
A' = 2A
Thus,
R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω.
Hope this helps!!
∴ Let the resistance of the wire originally 'R' of length 'L' and area of cross-section 'A' with resistivity of material is 'p',
Then
R = p l/A = 4Ω
Now, for new arrangement,
p' = p
l' = l / 2
A' = 2A
Thus,
R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω.
Hope this helps!!
Answered by
1
Answer:
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Explanation:
please check the answer in the above answer
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