Question

A nichrome wire of 4 ohm resistance is doubled on it. calculate the new resistance of the wire.

Answer 1

We consider wire is doubled on it means to fold the length of wire. It means its length will get half and area of cross section will get doubled.
∴ Let the resistance of the wire originally 'R' of length 'L' and area of cross-section 'A' with resistivity of material is 'p', 
Then
R = p l/A = 4Ω
Now, for new arrangement,
p' = p
l' = l / 2
A' = 2A
Thus, 
R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω.
Hope this helps!!

Answer 2

Answer:

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Explanation:

please check the answer in the above answer