a niggga was driving at 20m/s. he applied brakes which generated force equal to -500 N find the distance after which the car will stop it if its mass is 100kg
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✳️ Niggga's speed = 20 m/s
✳️ Final velocity acquired by Niggga = 0 [As, Niggga's car will finally stop after applying the brakes, and the velocity will become zero ultimately]
✳️ Force applied (F) = -500N
✳️ Mass of the Niggga's car = 100 kg
✳️ We know, v² - u² = 2 aS [Here, symbols have their usual meanings]
Putting the values of the known quantities we get,
(0)² - (20)² = 2. -500/100. S [Since, a = F/m]
=> -400 = -1000/100.s
=> -400 = -10.s [Note : "." represents multiplication symbol]
=> s = -400/-10 = 40
Hence, the required distance after which the car will stop is 40 metre.
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car will stops in 40 meter
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