Question

A NO CONSIIST OF 2 DIGITS THE SUM OF THE DIGIT IS 11 ON REVERSING THE DIGITS THE TOTAL BECOMES LESS BY 63. THE NUMBER IS ?

Answer 1

let's take the number be 10x+y where x is the digit in tens place and y is in ones place.So sum of digits =11=x+y. on reversing the number becomes 10y+x.
it is given upon reversing total is less than 63.this means 10y+x-10x-y=63. upon simplification it becomes y-x=7.solving both equations gives y=9andx=2. The original number is 29.

Answer 2

Let the tens place digit be x
and ones place be y
x+ y = 11 ..... (i)
Original Number = 10x +y
According to the question
10y +x =10x +y -63
9x -9y =63
x-y = 7 ....(ii)
Subtract equation (ii) from equation (i)
2y =4
y = 4/2
y = 2
Put the value in equation (i), we get
x+2 =11
x = 11-2
x =9
Original Number = 10x+y = 10(9)+2 =92