Question

A NO. consist of 2 digits whose sum
is 5 when the digits are reversed
the no. becomes greater by 9 find
the No.
​

Answer 1

●Digit at unit place be x

●Digit at tens place will ne 5-x

●Then the no. will ne 10(5-x)+x

●The no. after interchange of digits will be (10x)+(5-x).

AS PER THE SITUATION GIVEN:-

{(10x)+(5-x)} - {10(5-x)+x} = 9

10x + 5-x - (50 - 10x + x) = 9

10x + 5-x - 50 +10x - x = 9

18x - 45 = 9

18x = 9 + 45

18x = 54

x = 54/18

x = 3

●The no. before interchange = 23

●The no. after interchange = 32

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