A no consist of two digits whose some is 8 , if 18 is add to the no, it's digit are reversed find the no
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Let the Ten's place digit be x and unit place digit be 8 - x ( ∵ sum of digits = 8)
Two digit number is of form 10 (Ten Place Digit) + Unit Place Digit
∴ Two digit number formed = 10 (x) + (8 - x)
= 10x + 8 - x
= 9x + 8
Number formed by reversing the digits = 10 ( 8 - x ) + x
= 80 - 10x + x
= 80 - 9x
According to question
Original Number + 18 = Number obtained by reversing the digits
∴ 9x + 8 + 18 = 80 - 9x
18x = 80 - 26
18x = 54
x = 3
∴ Original number = 9x + 8 = 35
35 is the desired number
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