Question

A no. consist of two digits
whose sum is 5. If we add 9 with
the no. ,the digits
in the no.
are internhanged.​ in one variable
i will mark you as brainliest​ with explanation please​

Answer 1

Answer:

Let’s assume the digit at unit’s place as x and ten’s place as y. Thus, the number to be found is 10y + x.

From the question it’s given as, the sum of the digits of the number is equal to 5.

Thus we can write, x + y = 5 ………….. (i)

On interchange the place of digits, the new number so formed will be 10x + y.

Again from the question it’s given as, the new number so obtained after interchanging the digits is greater by 9 from the original number. Therefore, this can be written as;

10x + y = 10y + x + 9

⇒ 10x + y – 10y – x = 9

⇒ 9x – 9y = 9

⇒ 9(x – y) = 9

⇒ x – y = 1………………. (ii)

Solving (i) and (ii), we can find x and y

Adding the eq. 1 and 2, we get;

(x + y) + (x – y) = 5 +1

⇒ x + y + x – y = 5 + 1

⇒ 2x = 6

⇒ x = 6/2

⇒ x = 3

Putting the value of x in the equation 1, we get;

3 + y = 5

⇒ y = 5 - 3

⇒ y = 2

Hence, the required number is 10 × 2 + 3 = 23

Hope you get your answer