Question

a no. consist of two digits whose sum is five. when the digits are reserved, the no. become greater by nine. find the no..

Answer 1

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Answer 2

Sol : Let the 10th place digit is x and  ones place digit is y.

So, number = 10x + y.

According to question ,

 x + y = 5  --------------- equation 1,

Again ,

When the digits are reversed then the number become greater by 9, so

 10y + x = 10x + y + 9

 10y - y + x - 10x = 9

 9y - 9x = 9

 9 ( y - x )= 9

 ( y - x ) = 9 /9

 ( y - x ) = 1  ---------------- equation 2

By adding equation 1 and equation 2,

 x + y + y - x = 5 + 1

 2y = 6

 y = 6 / 2

y = 3.

By substituting the value of y in equation 1 ,

 x + y = 5

 x + 3 = 5

 x = 5 - 3

 x = 2.

Number = 10x + y = 10 x 2 + 3 = 20 + 3 = 23.


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