A no. consists of 2 digits when it is divided by the sum of digits the quotient is 6 with no remainder. When the no. is diminished by 9 the digits are reversed. Find the nos.
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as the no reverses by subtracting 9 so right minus left should be -1 and no. must be a multiple of 6 so 54 is the ans.
Shreya2103:
can u pls type the whole ans
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We know that Dividend=Divisor×Quotient+Remainder
Let the tens and the units digits of the required number be x and y,Respectively.
Required number=10x+y
10x+y=(x+y)×6+0
⇒10x−6x+y−6y=0
⇒4x−5y=0 ...(1)
Number obtained on reversing its digits=10y+x
∴10x+y−9=10y+x
⇒9x−9y=9 or x−y=1 ...(2)
On multiplying (2) by 5, we get
5x−5y=5 ...(3)
On subtracting (1) from (3),we get
x=5
On substituting x=5 in (1), we get
4×5−5y=0
⇒20−5y=0
⇒y=4
∴The number =10x+y=10×5+4=50+4=54
Hence the required number is 54
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