A no. consists of two digit of which tens digit exceed s the units digit by 6. the no. itself is equal to 10times the sum of its digits. find the no.
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the required number is 60
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Let's take the units digit be 'x'
So, ten's digit will be 'x+6'
The sum of the numbers is 10 times
So,*10
(In the standard form of any number let's take 10
So here
1 is multiplied by 10
whereas, 0 is multiplied by 1
thus we get 10)
assuming the above lines our ten's digit number will be multiplied by 10 ---
(x+6)(10) = 10x+60
same way 'x' will be multiplied by 1 which results in x
Now, let's find out x
Since the sum of the two digits equals to 10
thus,
(x+6)+(x) = 10
2x+6 =10
2x = 10-6
2x = 4
x =2
NOW WHY AREN'T WE USING 10X+60?
well only because it will only apply to the final numbers and not when we are adding . Example-1+0=2 whereas 10+0=10 and not 2
We are using the first example here
10(2)+60 =80 -------- 1
X=2 ---------2
THUS THE FINAL NUMBER IS 80+2=82
hope I helped you
So, ten's digit will be 'x+6'
The sum of the numbers is 10 times
So,*10
(In the standard form of any number let's take 10
So here
1 is multiplied by 10
whereas, 0 is multiplied by 1
thus we get 10)
assuming the above lines our ten's digit number will be multiplied by 10 ---
(x+6)(10) = 10x+60
same way 'x' will be multiplied by 1 which results in x
Now, let's find out x
Since the sum of the two digits equals to 10
thus,
(x+6)+(x) = 10
2x+6 =10
2x = 10-6
2x = 4
x =2
NOW WHY AREN'T WE USING 10X+60?
well only because it will only apply to the final numbers and not when we are adding . Example-1+0=2 whereas 10+0=10 and not 2
We are using the first example here
10(2)+60 =80 -------- 1
X=2 ---------2
THUS THE FINAL NUMBER IS 80+2=82
hope I helped you
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