Question

A no. consists of two digits whose sum is 8. If 18 is added to the no. its digits are reversed. Find the number.

Answer 1

Let the tens digit be y

and ones digit be x

$x + y = 8$

- 1

$10y + x + 18 = 10x + y$

$9(x - y) = 18$

$x - y = 2$

-2

from 1 & 2

$x = 5$

$y = 3$

the original no. is

$35$

thank you :))

Answer 2

Answer:

Step-by-step explanation:

Let the number be 10x+y

1st equation

x+y = 8

2nd equation

10y+x = 10x+y+18

9y–9x = 18

y–x = 2

Equate 1st and 2nd equation

x+y = 8

–x+y = 2

2y = 10

y = 5

x+y = 8

x+5 = 8

x = 3

The numbers are

For 10x+y = 30+5 = 35

For 10y+x = 50+3 = 53

Hope this helps you