Question

A no increased by 10% and then it is reduced by 10% find total increase or decreased percent

Answer 1

let original no. be x.
after increase, it is 11x/10.
on reduction, it becomes=99x/100.
Decreased % =1%

Answer 2

Let the number be x

When it is increased by 10%, the number becomes
$x + ( \frac{10x}{100}) \\ = x + \frac{x}{10} \\ = \frac{11x}{10}$
Again when it is decreased by 10%, it becomes

$\frac{11x}{10} - \frac{11x}{10} \times \frac{10}{100} \\ = \frac{11x}{10} - \frac{11x}{100} \\ = \frac{99x}{100}$
Thus, the number decreases.

The Percentage decrease

$= \frac{(x - \frac{99x}{100}) }{x} \times 100\% \\ = \frac{ \frac{x}{100} }{x} \times 100\% \\ = \frac{1}{100} \times 100\% \\ = 1\%$

Therefore, the number decreases by 1%.


★★ HOPE THAT HELPS ☺️ ★★