Math, asked by upendrakumar23peou4j, 1 year ago

a no. is increase by 10% and the increase no. is decreased by 10% .show that the net decrease is 1%

Answers

Answered by markmobley17pejfso
1

Solution :-


Let the required number be 100.


Then, according to the question.


⇒ Firstly, the number is increased by 10 %


⇒ 100 + (100*10)/100


⇒ 100 + 10


= 110


Secondly, it is decreased by 10 % 


⇒ 110 - (110*10)/100


⇒ 110 - 11


⇒ 99


Net increase or decrease percentage


= (Original Number - New Number)*100/100


⇒ (100 - 99)*100/100


⇒ (1*100)/100


⇒ 100/100


= 1 %


So, net decrease is 1 %.


Answer.




Answered by Anonymous
0
this question solve by two methods
first method-
in the pic

second method-

let the number= 100
it increases by 10%
so 100 + (100×10)/100
= 100 + 10
= 110

then it decreases by 10%
so 110-(110×10)/100
= 110 - 11
= 99

so 100-99 = 1
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